I have a grid with the “Add” button on the Product details page. As soon as I create a new record for this grid, I want to open the page of this record. I tried to use the steps “Load Page” and “Load a page from a grid”, but failed because of the wrong “pagestate” parameter (which, I assume, by default equals a Product details page state, not the newly created record page state). How to configure a process properly to open a details page for newly created grid record, and which step to use?
Hi Kate, you can simple add the default add-button to the grid:
The add-button on a grid that is placed on de pagerecord does have some consequences:
- A required foreign key to the pagerecordtype is created at the datasource record of the grid
- A default filter (this filter is merged with the normal filter) is added to the grid: new_foreign_key.equals(parent)
- A default process is added to the add-button namely: lock record, update record, load page.
If you do not like these consequence you can add an execute button. The process for the execute button is in principle the same as the processe that is automatically created after adding the add-button:
- Lock new record (data type is the grid type)
- Update record (to set some default values of the lock new record.record)
- Load page of the grid type with the record parameter set to lock new record.record). In this case you leave the pagestate empty because as you discoverd yourself the pagestate belongs to the pagerecord and not the grid record.
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